What is the tangent of y=9x-6sqrt(x)(1.3) ?

The tangent of y=9x-6sqrt(x)(1.3) is y=(9-(3.9)/(sqrt(a_{0))})x-3.9sqrt(a_{0)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=9x-6sqrt(x)(1.3)

tangent of

y = 9 x - 6 x (1.3)

y = (9 - \frac{3.9}{a _{0}}) x - 3.9 a_{0}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 9 a_{0} - 7.8 a_{0})

Find the slope of

y = 9 x - 6 x 1.3 : \frac{d y}{d x} = 9 - \frac{3.9}{x}

Compute the slope of

y = 9 x - 6 x 1.3

x = a_{0} : m = 9 - \frac{3.9}{a _{0}}

Find the line with slope m=

9 - \frac{3.9}{a _{0}}

and passing through

(a_{0}, 9 a_{0} - 7.8 a_{0}) : y = (9 - \frac{3.9}{a _{0}}) x - 3.9 a_{0}

y = (9 - \frac{3.9}{a _{0}}) x - 3.9 a_{0}

t^{2} y^{^{'}} + t y = 4, y (1) = 6

f (x) = 2^{x^{3}}

x = 2 y, y^{2} = 4 x

\frac{d}{d x} (\frac{x - 1}{x + 1})

\int 7 d x

What is the tangent of y=9x-6sqrt(x)(1.3) ?
The tangent of y=9x-6sqrt(x)(1.3) is y=(9-(3.9)/(sqrt(a_{0))})x-3.9sqrt(a_{0)}