What is the tangent of f(x)=((2x-1))/((x+5)),\at x=3 ?

The tangent of f(x)=((2x-1))/((x+5)),\at x=3 is y= 11/64 x+7/64

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=((2x-1))/((x+5)),\at x=3

tangent of

f (x) = \frac{( 2 x - 1 )}{( x + 5 )}, at x = 3

y = \frac{11}{64} x + \frac{7}{64}

Solution steps

Find the tangent point:

(3, \frac{5}{8})

Find the slope of

f (x) = \frac{2 x - 1}{x + 5} : \frac{df ( x )}{d x} = \frac{11}{( x + 5 ) ^{2}}

Compute the slope of

f (x) = \frac{2 x - 1}{x + 5}

x = 3 : m = \frac{11}{64}

Find the line with slope m=

\frac{11}{64}

and passing through

(3, \frac{5}{8}) : y = \frac{11}{64} x + \frac{7}{64}

y = \frac{11}{64} x + \frac{7}{64}

x \to 0 lim ((1 + x)^{\frac{4}{x}})

x^{2} y^{^{''}} + x y^{^{'}} + 4 y = 0

\frac{\partial}{\partial y} (3 x^{2} + y)

\int (sec^{3} (x)) d x

f (x) = x^{2} - 5 x + 5, (0, 5)

What is the tangent of f(x)=((2x-1))/((x+5)),\at x=3 ?
The tangent of f(x)=((2x-1))/((x+5)),\at x=3 is y= 11/64 x+7/64