What is the integral from 0 to infinity of 5e^{-x} ?

The integral from 0 to infinity of 5e^{-x} is 5

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integral from 0 to infinity of 5e^{-x}

\int_{0}^{\infty} 5 e^{- x} d x

5

Solution steps

\int_{0}^{\infty} 5 e^{- x} d x

Compute the indefinite integral:

\int 5 e^{- x} d x = - 5 e^{- x} + C

Compute the boundaries:

\int_{0}^{\infty} 5 e^{- x} d x = 0 - (- 5)

= 0 - (- 5)

Simplify

= 5

f (x) = cos (3 x^{2})

x \to π + lim (sec (x))

\frac{\partial ^{3}}{\partial x \partial y \partial z} (e^{x y z^{5}})

\frac{2}{( ( s - 4 ) s ( s + 1 ) )}

\int x^{2} + 4 x - 8 d x

What is the integral from 0 to infinity of 5e^{-x} ?
The integral from 0 to infinity of 5e^{-x} is 5