What is the derivative of y=2sin(4x) ?

The derivative of y=2sin(4x) is 8cos(4x)

What is the first derivative of y=2sin(4x) ?

The first derivative of y=2sin(4x) is 8cos(4x)

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derivative of

y = 2 sin (4 x)

8 cos (4 x)

Solution steps

\frac{d}{d x} (2 sin (4 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (sin (4 x))

Apply the chain rule:

cos (4 x) \frac{d}{d x} (4 x)

= cos (4 x) \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= 2 cos (4 x) \cdot 4

Simplify

= 8 cos (4 x)

y^{^{'}} - \frac{8}{x} y = \frac{y ^{3}}{x ^{11}}

x \to 3 - lim (∣ x - 3 ∣)

\frac{d y}{d t} = 3 y (y - 2)

x y^{^{'}} + y = 2 x^{2}

\frac{d}{d x} (- 2 x + 9)

What is the derivative of y=2sin(4x) ?
The derivative of y=2sin(4x) is 8cos(4x)
What is the first derivative of y=2sin(4x) ?
The first derivative of y=2sin(4x) is 8cos(4x)