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Popular >

xy^'+y=2x^2

Solution

x y^{^{'}} + y = 2 x^{2}

Solution

y = \frac{2 x ^{2}}{3} + \frac{c _{1}}{x}

Solution steps

x y^{'} (x) + y = 2 x^{2}

Solve linear ODE:

y = \frac{2 x ^{2}}{3} + \frac{c _{1}}{x}

y = \frac{2 x ^{2}}{3} + \frac{c _{1}}{x}

Popular Examples

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y = \frac{π x}{12}

derivative of 2e^{-x}cos(x)

\frac{d}{d x} (2 e^{- x} cos (x))

Frequently Asked Questions (FAQ)

What is the solution for xy^'+y=2x^2 ?
The solution for xy^'+y=2x^2 is y=(2x^2)/3+(c_{1})/x