What is the derivative of f(x)=5e^x+8/(\sqrt[3]{x)} ?

The derivative of f(x)=5e^x+8/(\sqrt[3]{x)} is 5e^x-8/(3x^{4/3)}

What is the first derivative of f(x)=5e^x+8/(\sqrt[3]{x)} ?

The first derivative of f(x)=5e^x+8/(\sqrt[3]{x)} is 5e^x-8/(3x^{4/3)}

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derivative of

5 e^{x} - \frac{8}{3 x ^{\frac{4}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (5 e^{x}) = 5 e^{x}

= 5 e^{x} - \frac{8}{3 x ^{\frac{4}{3}}}

\frac{\partial}{\partial y} (x^{2} y - x y^{2})

y = \frac{tan ( x ) - 1}{sec ( x )}

y^{^{'''}} - 9 y^{^{''}} + y^{^{'}} - 9 y = 0

y^{^{''}} - 4 y^{^{'}} + 3 y = (2 x + 1) e^{- x}

x \to 0 - lim (\frac{0}{x ^{2} ∣ x ∣})

What is the derivative of f(x)=5e^x+8/(\sqrt[3]{x)} ?
The derivative of f(x)=5e^x+8/(\sqrt[3]{x)} is 5e^x-8/(3x^{4/3)}
What is the first derivative of f(x)=5e^x+8/(\sqrt[3]{x)} ?
The first derivative of f(x)=5e^x+8/(\sqrt[3]{x)} is 5e^x-8/(3x^{4/3)}