What is the integral of ((x^3))/3 ?

The integral of ((x^3))/3 is (x^4)/(12)+C

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integral of ((x^3))/3

\int \frac{( x ^{3} )}{3} d x

\frac{x ^{4}}{12} + C

Solution steps

\int \frac{x ^{3}}{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int x^{3} d x

Apply the Power Rule

: \frac{x ^{4}}{4}

= \frac{1}{3} \cdot \frac{x ^{4}}{4}

Simplify

\frac{1}{3} \cdot \frac{x ^{4}}{4} : \frac{x ^{4}}{12}

= \frac{x ^{4}}{12}

Add a constant to the solution

= \frac{x ^{4}}{12} + C

y = 3 x^{2} + 17 x + 10

\frac{\partial}{\partial x} (x^{2} y + x + y)

2 y^{^{''}} - 2 y^{^{'}} + 5 y = 0

\frac{d}{d x} (\frac{e ^{x}}{3 + e ^{x}})

\frac{d}{d x} (7 sin (x) - 2 x^{3})