What is the limit as x approaches 0 of (4e^x-4)/x ?

The limit as x approaches 0 of (4e^x-4)/x is 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of (4e^x-4)/x

x \to 0 lim (\frac{4 e ^{x} - 4}{x})

4

Solution steps

x \to 0 lim (\frac{4 e ^{x} - 4}{x})

Apply L'Hopital's Rule

: x \to 0 lim (\frac{4 e ^{x}}{1})

= x \to 0 lim (\frac{4 e ^{x}}{1})

Plug in the value

x = 0

= \frac{4 e ^{0}}{1}

Simplify

= 4

\frac{d}{d r} (\frac{1}{2 r} + \frac{1}{3 r ^{\frac{2}{3}}})

\frac{d}{d x} (f (h, x) (g (h, x) (h (x))))

\frac{\partial}{\partial x} (\frac{5 x + 4 y}{x + y})

\frac{\partial}{\partial x} (e^{x yz - 8})

(x + 1)^{2}

What is the limit as x approaches 0 of (4e^x-4)/x ?
The limit as x approaches 0 of (4e^x-4)/x is 4