What is (\partial)/(\partial x)(e^{xyz-8}) ?

The answer to (\partial)/(\partial x)(e^{xyz-8}) is e^{xyz-8}yz

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(e^{xyz-8})

\frac{\partial}{\partial x} (e^{x yz - 8})

e^{x yz - 8} yz

Solution steps

\frac{\partial}{\partial x} (e^{x yz - 8})

Treat

y, z

as constants

Apply the chain rule:

e^{x yz - 8} \frac{\partial}{\partial x} (x yz - 8)

= e^{x yz - 8} \frac{\partial}{\partial x} (x yz - 8)

\frac{\partial}{\partial x} (x yz - 8) = yz

= e^{x yz - 8} yz

(x + 1)^{2}

y^{^{'}} = \frac{2 x + sec ^{2} ( x )}{2 y}, y (0) = - 7

\frac{d}{d x} (2^{(2 - x^{4})})

\frac{d y}{d x} = \frac{x ^{3} + 2 y ^{3}}{x y ^{2}}

\int (\frac{( 3 x - 2 ) ^{2} + ( 3 x + 2 ) ^{2}}{x ^{2}}) d x

What is (\partial)/(\partial x)(e^{xyz-8}) ?
The answer to (\partial)/(\partial x)(e^{xyz-8}) is e^{xyz-8}yz