What is the integral from 2 to sqrt(6 of)x ?

The integral from 2 to sqrt(6 of)x is 1

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integral from 2 to sqrt(6 of)x

\int_{2}^{6} x d x

1

Solution steps

\int_{2}^{6} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{2}^{6}

= [\frac{x ^{2}}{2}]_{2}^{6}

Compute the boundaries:

1

= 1

(\frac{x ^{2} + 3}{x ^{2} - 3})^{3}

\frac{\partial}{\partial x} (x \cdot e^{x y})

x = y^{2} - 1, x = y

\frac{d}{d x} (x^{3} - 6 x^{2} + 9 x + 1)

\frac{d}{d x} (2 x + x^{2})

What is the integral from 2 to sqrt(6 of)x ?
The integral from 2 to sqrt(6 of)x is 1