What is the tangent of f(x)=(5x)/(x-2),\at x=3 ?

The tangent of f(x)=(5x)/(x-2),\at x=3 is y=-10x+45

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=(5x)/(x-2),\at x=3

tangent of

f (x) = \frac{5 x}{x - 2}, at x = 3

y = - 10 x + 45

Solution steps

Find the tangent point:

(3, 15)

Find the slope of

f (x) = \frac{5 x}{x - 2} : \frac{df ( x )}{d x} = - \frac{10}{( x - 2 ) ^{2}}

Compute the slope of

f (x) = \frac{5 x}{x - 2}

x = 3 : m = - 10

Find the line with slope m=

- 10

and passing through

(3, 15) : y = - 10 x + 45

y = - 10 x + 45

\frac{d}{d x} (16 e^{- 2 x})

n = 3 \sum \infty \frac{3}{2} \cdot \frac{1}{4 ^{n}}

\int_{0}^{8} f (x) d x

\frac{d x}{d t} = \frac{2 t ^{2} + x ^{2}}{t x}

\frac{d ^{2}}{d x ^{2}} (x^{\frac{1}{2}})

What is the tangent of f(x)=(5x)/(x-2),\at x=3 ?
The tangent of f(x)=(5x)/(x-2),\at x=3 is y=-10x+45