What is the derivative of 1/(8x^{7/8}) ?

The derivative of 1/(8x^{7/8}) is -7/(64x^{15/8)}

What is the first derivative of 1/(8x^{7/8}) ?

The first derivative of 1/(8x^{7/8}) is -7/(64x^{15/8)}

Popular >

\frac{d}{d x} (\frac{1}{8 x ^{\frac{7}{8}}})

- \frac{7}{64 x ^{\frac{15}{8}}}

Solution steps

\frac{d}{d x} (\frac{1}{8 x ^{\frac{7}{8}}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{8} \frac{d}{d x} (\frac{1}{x ^{\frac{7}{8}}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{8} \frac{d}{d x} (x^{- \frac{7}{8}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{8} (- \frac{7}{8} x^{- \frac{7}{8} - 1})

Simplify

\frac{1}{8} (- \frac{7}{8} x^{- \frac{7}{8} - 1}) : - \frac{7}{64 x ^{\frac{15}{8}}}

= - \frac{7}{64 x ^{\frac{15}{8}}}

\frac{d}{d x} (7 cos^{3} (x))

2 x^{2} \frac{d y}{d x} = π y sin (\frac{π}{2 x})

y = ∣ x ∣ + ∣ x - 1 ∣, x = - 1, x = 2

\frac{d}{d x} (\frac{( x ^{3} + i x ^{2} + x + 1 )}{x ^{2} + i})

\int (1 - y) d y

What is the derivative of 1/(8x^{7/8}) ?
The derivative of 1/(8x^{7/8}) is -7/(64x^{15/8)}
What is the first derivative of 1/(8x^{7/8}) ?
The first derivative of 1/(8x^{7/8}) is -7/(64x^{15/8)}