What is area f(x)=-5/(x^3),y=0,x=-4,x=-1 ?

The answer to area f(x)=-5/(x^3),y=0,x=-4,x=-1 is 75/32

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area f(x)=-5/(x^3),y=0,x=-4,x=-1

area

f (x) = - \frac{5}{x ^{3}}, y = 0, x = - 4, x = - 1

\frac{75}{32}

Decimal Notation

2.34375

Solution steps

Apply the area formula:

\int_{- 4}^{- 1} \frac{5}{∣ x ^{3} ∣} d x

Solve

\int_{- 4}^{- 1} \frac{5}{∣ x ^{3} ∣} d x : \frac{75}{32}

The area is:

= \frac{75}{32}

x \to 0 lim (\frac{x}{csc ^{2} ( x )})

x \to 5 lim (x^{2} - 2 x + 1)

\frac{\partial}{\partial x} (5 e^{yz} cos (x yz))

x^{2} - 8 x + 15, 0

What is area f(x)=-5/(x^3),y=0,x=-4,x=-1 ?
The answer to area f(x)=-5/(x^3),y=0,x=-4,x=-1 is 75/32