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2x^4y^'=kintegral of (2x^3+6x)^2(\partial)/(\partial x)(5ln(sqrt(xy)))x^{''}+20x^'+500x=12integral from 0 to 4 of sqrt(x)-x+2
Frequently Asked Questions (FAQ)
What is the (dy)/(dx)= 1/3 y(8-y),y(0)=1 ?
The (dy)/(dx)= 1/3 y(8-y),y(0)=1 is 8/3-y/3