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Popular Calculus >

2x^4y^'=k

Solution

2 x^{4} y^{^{'}} = k

Solution

y = - \frac{k}{6 x ^{3}} + c_{1}

Solution steps

2 x^{4} y^{'} (x) = k

Isolate

y^{'} (x) : y^{'} (x) = \frac{k}{2 x ^{4}}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int \frac{k}{2 x ^{4}} d x

\int \frac{k}{2 x ^{4}} d x = - \frac{k}{6 x ^{3}} + c_{1}

y = - \frac{k}{6 x ^{3}} + c_{1}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for 2x^4y^'=k ?
The solution for 2x^4y^'=k is y=-k/(6x^3)+c_{1}