What is the derivative of f(x)=9x^{7/5}-5x^2+10^4 ?

The derivative of f(x)=9x^{7/5}-5x^2+10^4 is -10x+(63x^{2/5})/5

What is the first derivative of f(x)=9x^{7/5}-5x^2+10^4 ?

The first derivative of f(x)=9x^{7/5}-5x^2+10^4 is -10x+(63x^{2/5})/5

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derivative of

f (x) = 9 x^{\frac{7}{5}} - 5 x^{2} + 1 0^{4}

- 10 x + \frac{63 x ^{\frac{2}{5}}}{5}

Solution steps

\frac{d}{d x} (9 x^{\frac{7}{5}} - 5 x^{2} + 1 0^{4})

Simplify

9 x^{\frac{7}{5}} - 5 x^{2} + 1 0^{4} : 9 x^{\frac{7}{5}} - 5 x^{2} + 10000

= \frac{d}{d x} (9 x^{\frac{7}{5}} - 5 x^{2} + 10000)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9 x^{\frac{7}{5}}) - \frac{d}{d x} (5 x^{2}) + \frac{d}{d x} (10000)

\frac{d}{d x} (9 x^{\frac{7}{5}}) = \frac{63 x ^{\frac{2}{5}}}{5}

\frac{d}{d x} (5 x^{2}) = 10 x

\frac{d}{d x} (10000) = 0

= \frac{63 x ^{\frac{2}{5}}}{5} - 10 x + 0

Simplify

= - 10 x + \frac{63 x ^{\frac{2}{5}}}{5}

3 x + sin (5 x)

y = \frac{x}{4 x + 7}

f (x) = ln (cos (x))

\frac{d}{d x} (9 e^{x})

x \to 0 lim (\frac{2 ^{x} - 5 ^{x}}{x})

What is the derivative of f(x)=9x^{7/5}-5x^2+10^4 ?
The derivative of f(x)=9x^{7/5}-5x^2+10^4 is -10x+(63x^{2/5})/5
What is the first derivative of f(x)=9x^{7/5}-5x^2+10^4 ?
The first derivative of f(x)=9x^{7/5}-5x^2+10^4 is -10x+(63x^{2/5})/5