What is the derivative of 3x+sin(5x) ?

The derivative of 3x+sin(5x) is 3+cos(5x)*5

What is the first derivative of 3x+sin(5x) ?

The first derivative of 3x+sin(5x) is 3+cos(5x)*5

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derivative of

3 x + sin (5 x)

3 + cos (5 x) \cdot 5

Solution steps

\frac{d}{d x} (3 x + sin (5 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (sin (5 x))

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (sin (5 x)) = cos (5 x) \cdot 5

= 3 + cos (5 x) \cdot 5

y = \frac{x}{4 x + 7}

f (x) = ln (cos (x))

\frac{d}{d x} (9 e^{x})

x \to 0 lim (\frac{2 ^{x} - 5 ^{x}}{x})

\frac{d}{d x} (2 x^{3} - 3 x^{2})

What is the derivative of 3x+sin(5x) ?
The derivative of 3x+sin(5x) is 3+cos(5x)*5
What is the first derivative of 3x+sin(5x) ?
The first derivative of 3x+sin(5x) is 3+cos(5x)*5