integral of (csc(x))^3

Lösung

\int (csc (x))^{3} d x

\frac{1}{8} (- cot^{2} (\frac{x}{2}) + 4 ln tan (\frac{x}{2}) + tan^{2} (\frac{x}{2})) + C

Schritte zur Lösung

\int (csc (x))^{3} d x

Vereinfache

= \int csc^{3} (x) d x

Wende U-Substitution an

= \int \frac{( 1 + u ^{2} ) ^{2}}{4 u ^{3}} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int \frac{( 1 + u ^{2} ) ^{2}}{u ^{3}} d u

Multipliziere aus

\frac{( 1 + u ^{2} ) ^{2}}{u ^{3}} : \frac{1}{u ^{3}} + \frac{2}{u} + u

= \frac{1}{4} \cdot \int \frac{1}{u ^{3}} + \frac{2}{u} + u d u

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{4} (\int \frac{1}{u ^{3}} d u + \int \frac{2}{u} d u + \int u d u)

\int \frac{1}{u ^{3}} d u = - \frac{1}{2 u ^{2}}

\int \frac{2}{u} d u = 2 ln ∣ u ∣

\int u d u = \frac{u ^{2}}{2}

= \frac{1}{4} (- \frac{1}{2 u ^{2}} + 2 ln ∣ u ∣ + \frac{u ^{2}}{2})

Setze in

u = tan (\frac{x}{2})

ein

= \frac{1}{4} (- \frac{1}{2 tan ^{2} ( \frac{x}{2} )} + 2 ln tan (\frac{x}{2}) + \frac{tan ^{2} ( \frac{x}{2} )}{2})

Vereinfache

\frac{1}{4} (- \frac{1}{2 tan ^{2} ( \frac{x}{2} )} + 2 ln tan (\frac{x}{2}) + \frac{tan ^{2} ( \frac{x}{2} )}{2}) : \frac{1}{8} (- cot^{2} (\frac{x}{2}) + 4 ln tan (\frac{x}{2}) + tan^{2} (\frac{x}{2}))

= \frac{1}{8} (- cot^{2} (\frac{x}{2}) + 4 ln tan (\frac{x}{2}) + tan^{2} (\frac{x}{2}))

Füge eine Konstante zur Lösung hinzu

= \frac{1}{8} (- cot^{2} (\frac{x}{2}) + 4 ln tan (\frac{x}{2}) + tan^{2} (\frac{x}{2})) + C

\int \frac{x}{x - 5} d x

\int + x e^{x} d x

\frac{\partial}{\partial y} (x - z - arctan (yz))

a re a y = x, y = \frac{x}{2}, x = 9

t an g e n t \frac{8}{x} + 6