What is the first derivative of x^2-6 ?

The first derivative of x^2-6 is 2x

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derivative of x^2-6

derivative of

x^{2} - 6

2 x

Solution steps

\frac{d}{d x} (x^{2} - 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (6)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (6) = 0

= 2 x - 0

Simplify

= 2 x

f (x) = x - 9

\int \frac{1}{- x ^{2} - 6 x + 40} d x

x \to 0 lim (cot^{2} (x))

x \to 2 lim (\frac{1}{x - 2})

\int \frac{x ^{2} + 4 x + 1}{x ^{3} + x} d x