What is the derivative of (2x+9^2) ?

The derivative of (2x+9^2) is 4(2x+9)

What is the first derivative of (2x+9^2) ?

The first derivative of (2x+9^2) is 4(2x+9)

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\frac{d}{d x} ((2 x + 9)^{2})

4 (2 x + 9)

Solution steps

\frac{d}{d x} ((2 x + 9)^{2})

Apply the chain rule:

2 (2 x + 9) \frac{d}{d x} (2 x + 9)

= 2 (2 x + 9) \frac{d}{d x} (2 x + 9)

\frac{d}{d x} (2 x + 9) = 2

= 2 (2 x + 9) \cdot 2

Simplify

= 4 (2 x + 9)

y = 3 + lo g_{2} (x)

d y = x^{2} d x

\frac{d}{d x} (\frac{2 x + 5}{2 x - 5})

\frac{\partial}{\partial x} (26 - x^{2} - y^{2})

\frac{d}{d x} (sec (x^{2} - 1))

What is the derivative of (2x+9^2) ?
The derivative of (2x+9^2) is 4(2x+9)
What is the first derivative of (2x+9^2) ?
The first derivative of (2x+9^2) is 4(2x+9)