What is the derivative of (x^2-2x)/((x-1)^2) ?

The derivative of (x^2-2x)/((x-1)^2) is 2/((x-1)^3)

What is the first derivative of (x^2-2x)/((x-1)^2) ?

The first derivative of (x^2-2x)/((x-1)^2) is 2/((x-1)^3)

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derivative of

\frac{x ^{2} - 2 x}{( x - 1 ) ^{2}}

\frac{2}{( x - 1 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 2 x}{( x - 1 ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} - 2 x ) ( x - 1 ) ^{2} - \frac{d}{d x} ( ( x - 1 ) ^{2} ) ( x ^{2} - 2 x )}{( ( x - 1 ) ^{2} ) ^{2}}

\frac{d}{d x} (x^{2} - 2 x) = 2 x - 2

\frac{d}{d x} ((x - 1)^{2}) = 2 (x - 1)

= \frac{( 2 x - 2 ) ( x - 1 ) ^{2} - 2 ( x - 1 ) ( x ^{2} - 2 x )}{( ( x - 1 ) ^{2} ) ^{2}}

Simplify

\frac{( 2 x - 2 ) ( x - 1 ) ^{2} - 2 ( x - 1 ) ( x ^{2} - 2 x )}{( ( x - 1 ) ^{2} ) ^{2}} : \frac{2}{( x - 1 ) ^{3}}

= \frac{2}{( x - 1 ) ^{3}}

f (x) = x^{4} + 9 e^{x}, (0, 9)

e^{x} y d y = (e^{- y} + e^{- 2 x - y}) d x

n = 0 \sum \infty \frac{n + 1}{n !}

\frac{d}{d θ} (3 + 3 sin (θ))

0

What is the derivative of (x^2-2x)/((x-1)^2) ?
The derivative of (x^2-2x)/((x-1)^2) is 2/((x-1)^3)
What is the first derivative of (x^2-2x)/((x-1)^2) ?
The first derivative of (x^2-2x)/((x-1)^2) is 2/((x-1)^3)