What is the solution for e^xydy=(e^{-y}+e^{-2x-y})dx ?

The solution for e^xydy=(e^{-y}+e^{-2x-y})dx is y=\W((-3/(e^x)-1/(e^{3x)}+c_{1})/(3e))+1

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e^xydy=(e^{-y}+e^{-2x-y})dx

e^{x} y d y = (e^{- y} + e^{- 2 x - y}) d x

y = W (\frac{- \frac{3}{e ^{x}} - \frac{1}{e ^{3 x}} + c _{1}}{3 e}) + 1

Solution steps

e^{x} y d y = (e^{- y} + e^{- 2 x - y}) d x

Solve separable ODE:

y = W (\frac{- \frac{3}{e ^{x}} - \frac{1}{e ^{3 x}} + c _{1}}{3 e}) + 1

y = W (\frac{- \frac{3}{e ^{x}} - \frac{1}{e ^{3 x}} + c _{1}}{3 e}) + 1

n = 0 \sum \infty \frac{n + 1}{n !}

\frac{d}{d θ} (3 + 3 sin (θ))

0

t + 2

\int - \frac{26}{x ^{27}} d x

What is the solution for e^xydy=(e^{-y}+e^{-2x-y})dx ?
The solution for e^xydy=(e^{-y}+e^{-2x-y})dx is y=\W((-3/(e^x)-1/(e^{3x)}+c_{1})/(3e))+1