What is the limit as x approaches infinity of log_{e}(x^2-1) ?

The limit as x approaches infinity of log_{e}(x^2-1) is infinity

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limit as x approaches infinity of log_{e}(x^2-1)

x \to \infty lim (lo g_{e} (x^{2} - 1))

\infty

Solution steps

x \to \infty lim (lo g_{e} (x^{2} - 1))

Apply log rule:

lo g_{e} (x) = ln (x)

= x \to \infty lim (ln (x^{2} - 1))

Apply the Limit Chain Rule:

\infty

= \infty

x \to 3 lim (f (x))

x y^{^{'}} + y = cos (x)

\int \frac{4 x \frac{5}{4} - 2 x \frac{1}{4}}{x \frac{1}{4}} d x

\int_{0}^{\frac{π}{2}} (3 cos^{2} (x)) d x

\frac{6}{s} + 8 a \cdot \frac{1}{s ^{2} + 16}

What is the limit as x approaches infinity of log_{e}(x^2-1) ?
The limit as x approaches infinity of log_{e}(x^2-1) is infinity