What is the integral from 0 to pi/2 of (3cos^2(x)) ?

The integral from 0 to pi/2 of (3cos^2(x)) is (3pi)/4

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integral from 0 to pi/2 of (3cos^2(x))

\int_{0}^{\frac{π}{2}} (3 cos^{2} (x)) d x

\frac{3 π}{4}

Decimal Notation

2.35619 \dots

Solution steps

\int_{0}^{\frac{π}{2}} 3 cos^{2} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{\frac{π}{2}} cos^{2} (x) d x

Rewrite using trig identities

= 3 \cdot \int_{0}^{\frac{π}{2}} \frac{1 + cos ( 2 x )}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \frac{1}{2} \cdot \int_{0}^{\frac{π}{2}} 1 + cos (2 x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 3 \cdot \frac{1}{2} (\int_{0}^{\frac{π}{2}} 1 d x + \int_{0}^{\frac{π}{2}} cos (2 x) d x)

\int_{0}^{\frac{π}{2}} 1 d x = \frac{π}{2}

\int_{0}^{\frac{π}{2}} cos (2 x) d x = 0

= 3 \cdot \frac{1}{2} (\frac{π}{2} + 0)

Simplify

3 \cdot \frac{1}{2} (\frac{π}{2} + 0) : \frac{3 π}{4}

= \frac{3 π}{4}

\frac{6}{s} + 8 a \cdot \frac{1}{s ^{2} + 16}

(\frac{1}{cos ^{2} ( x )})^{^{'}}

\int 3 sec^{2} (x) d x

x \to 5 lim (2 x^{3} - 3 x + 8)

x^{2} + x, at x = - 4

What is the integral from 0 to pi/2 of (3cos^2(x)) ?
The integral from 0 to pi/2 of (3cos^2(x)) is (3pi)/4