What is the integral of (4x 5/4-2x 1/4)/(x 1/4) ?

The integral of (4x 5/4-2x 1/4)/(x 1/4) is 18x+C

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integral of (4x 5/4-2x 1/4)/(x 1/4)

\int \frac{4 x \frac{5}{4} - 2 x \frac{1}{4}}{x \frac{1}{4}} d x

18 x + C

Solution steps

\int \frac{4 x \frac{5}{4} - 2 x \frac{1}{4}}{x \frac{1}{4}} d x

\frac{4 x \frac{5}{4} - 2 x \frac{1}{4}}{x \frac{1}{4}} = 18

= \int 18 d x

Integral of a constant:

\int a d x = a x

= 18 x

Add a constant to the solution

= 18 x + C

\int_{0}^{\frac{π}{2}} (3 cos^{2} (x)) d x

\frac{6}{s} + 8 a \cdot \frac{1}{s ^{2} + 16}

(\frac{1}{cos ^{2} ( x )})^{^{'}}

\int 3 sec^{2} (x) d x

x \to 5 lim (2 x^{3} - 3 x + 8)

What is the integral of (4x 5/4-2x 1/4)/(x 1/4) ?
The integral of (4x 5/4-2x 1/4)/(x 1/4) is 18x+C