What is the tangent of f(x)= 2/x ,(4, 1/2) ?

The tangent of f(x)= 2/x ,(4, 1/2) is y=-1/8 x+1

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tangent of f(x)= 2/x ,(4, 1/2)

tangent of

f (x) = \frac{2}{x}, (4, \frac{1}{2})

y = - \frac{1}{8} x + 1

Solution steps

Find the slope of

f (x) = \frac{2}{x} : \frac{df ( x )}{d x} = - \frac{2}{x ^{2}}

Compute the slope of

f (x) = \frac{2}{x}

(4, \frac{1}{2}) : m = - \frac{1}{8}

Find the line with slope m=

- \frac{1}{8}

and passing through

(4, \frac{1}{2}) : y = - \frac{1}{8} x + 1

y = - \frac{1}{8} x + 1

\frac{d}{d x} (1 + 2 cos (x))

\frac{d}{d x} (e^{x^{2} - 4} + 3 x + 5)

(- 4, 4), (3, - 4)

(y^{2} + y x) d x + (x^{2}) d y = 0

y = (x - 2)^{4}

What is the tangent of f(x)= 2/x ,(4, 1/2) ?
The tangent of f(x)= 2/x ,(4, 1/2) is y=-1/8 x+1