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Popular >

integral from 0 to 4 of (2t+4)

Solution

\int_{0}^{4} (2 t + 4) d t

Solution

32

Solution steps

\int_{0}^{4} 2 t + 4 d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 2 t d t + \int_{0}^{4} 4 d t

\int_{0}^{4} 2 t d t = 16

\int_{0}^{4} 4 d t = 16

= 16 + 16

Simplify

= 32

Popular Examples

derivative of 10(4e^{x^2}x^3+6e^{x^2}x)derivative of

10 (4 e^{x^{2}} x^{3} + 6 e^{x^{2}} x)

limit as x approaches 0 of log_{10}(x)

x \to 0 lim (lo g_{10} (x))

integral of 1/(x^2sqrt(x^2+16))

\int \frac{1}{x ^{2} x ^{2} + 16} d x

y^{^{''}} - 2 y + 1 = 0

derivative of sqrt(x^2-11y^2),yas derivative of

x^{2} - 11 y^{2}, y a s

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of (2t+4) ?
The integral from 0 to 4 of (2t+4) is 32