What is the tangent of f(x)=(2x-4)/(sqrt(x)),\at x=4 ?

The tangent of f(x)=(2x-4)/(sqrt(x)),\at x=4 is y= 3/4 x-1

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tangent of f(x)=(2x-4)/(sqrt(x)),\at x=4

tangent of

f (x) = \frac{2 x - 4}{x}, at x = 4

y = \frac{3}{4} x - 1

Solution steps

Find the tangent point:

(4, 2)

Find the slope of

f (x) = \frac{2 x - 4}{x} : \frac{df ( x )}{d x} = \frac{x + 2}{x x}

Compute the slope of

f (x) = \frac{2 x - 4}{x}

x = 4 : m = \frac{3}{4}

Find the line with slope m=

\frac{3}{4}

and passing through

(4, 2) : y = \frac{3}{4} x - 1

y = \frac{3}{4} x - 1

\int - \frac{4}{25} x + 58 d x

\int (\frac{2 x - 5}{7}) d x

\int (sec^{2} (x) - 9) d x

\int_{0}^{2} \frac{3 x ^{2} - 1}{x ^{2}} d x

y = 2 x^{3} - x^{2} + 7

What is the tangent of f(x)=(2x-4)/(sqrt(x)),\at x=4 ?
The tangent of f(x)=(2x-4)/(sqrt(x)),\at x=4 is y= 3/4 x-1