What is the tangent of y=5xtan(x),\at x=pi ?

The tangent of y=5xtan(x),\at x=pi is y=5pix-5pi^2

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tangent of y=5xtan(x),\at x=pi

tangent of

y = 5 x tan (x), at x = π

y = 5 π x - 5 π^{2}

Solution steps

Find the tangent point:

(π, 0)

Find the slope of

y = 5 x tan (x) : \frac{d y}{d x} = 5 (tan (x) + x sec^{2} (x))

Compute the slope of

y = 5 x tan (x)

x = π : m = 5 π

Find the line with slope m=

5 π

and passing through

(π, 0) : y = 5 π x - 5 π^{2}

y = 5 π x - 5 π^{2}

f (x) = 3^{x^{5}}

x \to 0 + lim (x^{(\frac{1}{x})})

x \to 1 - lim (x + 3)

\frac{d y}{d t} + 3 y = 13 sin (2 t), y (0) = 6

f (x) = x^{4} + 7 x^{2} - x, (1, 7)

What is the tangent of y=5xtan(x),\at x=pi ?
The tangent of y=5xtan(x),\at x=pi is y=5pix-5pi^2