What is the tangent of f(x)=x^4+7x^2-x,(1,7) ?

The tangent of f(x)=x^4+7x^2-x,(1,7) is y=17x-10

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tangent of f(x)=x^4+7x^2-x,(1,7)

tangent of

f (x) = x^{4} + 7 x^{2} - x, (1, 7)

y = 17 x - 10

Solution steps

Find the slope of

f (x) = x^{4} + 7 x^{2} - x : \frac{df ( x )}{d x} = 4 x^{3} + 14 x - 1

Compute the slope of

f (x) = x^{4} + 7 x^{2} - x

(1, 7) : m = 17

Find the line with slope m=

17

and passing through

(1, 7) : y = 17 x - 10

y = 17 x - 10

\int_{0}^{3} (x^{3} - x) d x

x \frac{d}{d x} (ln (y)) = 1

x \to 2 + lim (\frac{1}{x + 2})

\frac{d}{d x} (33 (10 x - x + 10.45))

x \to 3 + lim (\frac{x - 4}{3 - x})

What is the tangent of f(x)=x^4+7x^2-x,(1,7) ?
The tangent of f(x)=x^4+7x^2-x,(1,7) is y=17x-10