What is the limit as x approaches 0+of x^{(1/x)} ?

The limit as x approaches 0+of x^{(1/x)} is 0

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limit as x approaches 0+of x^{(1/x)}

x \to 0 + lim (x^{(\frac{1}{x})})

0

Solution steps

x \to 0 + lim (x^{\frac{1}{x}})

Apply exponent rules

= x \to 0 + lim (e^{\frac{1}{x} l n (x)})

Apply the Limit Chain Rule:

0

= 0

x \to 1 - lim (x + 3)

\frac{d y}{d t} + 3 y = 13 sin (2 t), y (0) = 6

f (x) = x^{4} + 7 x^{2} - x, (1, 7)

\int_{0}^{3} (x^{3} - x) d x

x \frac{d}{d x} (ln (y)) = 1

What is the limit as x approaches 0+of x^{(1/x)} ?
The limit as x approaches 0+of x^{(1/x)} is 0