What is the derivative of x^3-3x^2+2x ?

The derivative of x^3-3x^2+2x is 3x^2-6x+2

What is the first derivative of x^3-3x^2+2x ?

The first derivative of x^3-3x^2+2x is 3x^2-6x+2

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\frac{d}{d x} (x^{3} - 3 x^{2} + 2 x)

3 x^{2} - 6 x + 2

Solution steps

\frac{d}{d x} (x^{3} - 3 x^{2} + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (2 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2 x) = 2

= 3 x^{2} - 6 x + 2

\frac{\partial}{\partial x} (x^{3} y^{3} + y - z + 3)

\frac{\partial}{\partial x} (x^{7} y^{8} - x^{6} y^{7})

e^{- 2 t} sin (3 t)

\int x csc^{2} (x) d x

x \to + (- 2) lim (\frac{- 9}{x ^{2}})

What is the derivative of x^3-3x^2+2x ?
The derivative of x^3-3x^2+2x is 3x^2-6x+2
What is the first derivative of x^3-3x^2+2x ?
The first derivative of x^3-3x^2+2x is 3x^2-6x+2