What is the derivative of f(x)=(x+x^4)(-x-1) ?

The derivative of f(x)=(x+x^4)(-x-1) is -5x^4-4x^3-2x-1

What is the first derivative of f(x)=(x+x^4)(-x-1) ?

The first derivative of f(x)=(x+x^4)(-x-1) is -5x^4-4x^3-2x-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = (x + x^{4}) (- x - 1)

- 5 x^{4} - 4 x^{3} - 2 x - 1

Solution steps

\frac{d}{d x} ((x + x^{4}) (- x - 1))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x + x^{4}, g = - x - 1

= \frac{d}{d x} (x + x^{4}) (- x - 1) + \frac{d}{d x} (- x - 1) (x + x^{4})

\frac{d}{d x} (x + x^{4}) = 1 + 4 x^{3}

\frac{d}{d x} (- x - 1) = - 1

= (1 + 4 x^{3}) (- x - 1) + (- 1) (x + x^{4})

Simplify

(1 + 4 x^{3}) (- x - 1) + (- 1) (x + x^{4}) : - 5 x^{4} - 4 x^{3} - 2 x - 1

= - 5 x^{4} - 4 x^{3} - 2 x - 1

y^{^{'}} sin (2 π x) = π y cos (2 π x)

x \to 1 - lim (4 - x - x^{2})

\frac{4}{s ^{3}}

\int x sin (7 - x) d x

\frac{d x}{d t} = x^{2} - 3

What is the derivative of f(x)=(x+x^4)(-x-1) ?
The derivative of f(x)=(x+x^4)(-x-1) is -5x^4-4x^3-2x-1
What is the first derivative of f(x)=(x+x^4)(-x-1) ?
The first derivative of f(x)=(x+x^4)(-x-1) is -5x^4-4x^3-2x-1