What is the solution for (dy)/(dx)= 1/(sqrt(x)) ?

The solution for (dy)/(dx)= 1/(sqrt(x)) is y=2sqrt(x)+c_{1}

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(dy)/(dx)= 1/(sqrt(x))

\frac{d y}{d x} = \frac{1}{x}

y = 2 x + c_{1}

Solution steps

\frac{d y}{d x} = \frac{1}{x}

Substitute

\frac{d y}{d x}

with

y^{'} (x)

y^{^{'}} (x) = \frac{1}{x}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int \frac{1}{x} d x

\int \frac{1}{x} d x = 2 x + c_{1}

y = 2 x + c_{1}

\int_{0}^{1} (e^{x^{2}}) d x

\frac{x}{y} \frac{d y}{d x} + ln (y) = x + 1

\int \frac{3}{4} x^{4} d x

x \to 2 + lim (\frac{2 x + 1}{x - 2})

cos (x^{5})

What is the solution for (dy)/(dx)= 1/(sqrt(x)) ?
The solution for (dy)/(dx)= 1/(sqrt(x)) is y=2sqrt(x)+c_{1}