What is the derivative of f(x)=-7/((x+4)^2) ?

The derivative of f(x)=-7/((x+4)^2) is (14)/((x+4)^3)

What is the first derivative of f(x)=-7/((x+4)^2) ?

The first derivative of f(x)=-7/((x+4)^2) is (14)/((x+4)^3)

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derivative of

f (x) = - \frac{7}{( x + 4 ) ^{2}}

\frac{14}{( x + 4 ) ^{3}}

Solution steps

\frac{d}{d x} (- \frac{7}{( x + 4 ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 7 \frac{d}{d x} (\frac{1}{( x + 4 ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 7 \frac{d}{d x} ((x + 4)^{- 2})

Apply the chain rule:

- \frac{2}{( x + 4 ) ^{3}} \frac{d}{d x} (x + 4)

= - \frac{2}{( x + 4 ) ^{3}} \frac{d}{d x} (x + 4)

\frac{d}{d x} (x + 4) = 1

= - 7 (- \frac{2}{( x + 4 ) ^{3}} \cdot 1)

Simplify

- 7 (- \frac{2}{( x + 4 ) ^{3}} \cdot 1) : \frac{14}{( x + 4 ) ^{3}}

= \frac{14}{( x + 4 ) ^{3}}

f (t) = (1) (t^{3})

\frac{d}{d x} (\frac{1}{16 x ^{4}})

- 3 y^{^{'}} + \frac{3 y}{x} = x y^{4}

\int \frac{x}{( x ^{2} - 3 ) ^{3}} d x

\int (4 sin (5 x) + 5 cos (3 x)) d x

What is the derivative of f(x)=-7/((x+4)^2) ?
The derivative of f(x)=-7/((x+4)^2) is (14)/((x+4)^3)
What is the first derivative of f(x)=-7/((x+4)^2) ?
The first derivative of f(x)=-7/((x+4)^2) is (14)/((x+4)^3)