What is laplacetransform f(t)=(1)(t^3) ?

The answer to laplacetransform f(t)=(1)(t^3) is 6/(s^4)

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laplacetransform f(t)=(1)(t^3)

laplace transform

f (t) = (1) (t^{3})

\frac{6}{s ^{4}}

Solution steps

L {(1) (t^{3})}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 1 L {t^{3}}

L {t^{3}} : \frac{6}{s ^{4}}

= 1 \cdot \frac{6}{s ^{4}}

Refine

1 \frac{6}{s ^{4}} : \frac{6}{s ^{4}}

= \frac{6}{s ^{4}}

\frac{d}{d x} (\frac{1}{16 x ^{4}})

- 3 y^{^{'}} + \frac{3 y}{x} = x y^{4}

\int \frac{x}{( x ^{2} - 3 ) ^{3}} d x

\int (4 sin (5 x) + 5 cos (3 x)) d x

- cos (x^{2}) sin (x) + e^{- x - 2}

What is laplacetransform f(t)=(1)(t^3) ?
The answer to laplacetransform f(t)=(1)(t^3) is 6/(s^4)