What is (\partial)/(\partial θ)(rcos(θ)) ?

The answer to (\partial)/(\partial θ)(rcos(θ)) is -rsin(θ)

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(\partial)/(\partial θ)(rcos(θ))

\frac{\partial}{\partial θ} (r cos (θ))

- r sin (θ)

Solution steps

\frac{\partial}{\partial θ} (r cos (θ))

Treat

r

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= r \frac{\partial}{\partial θ} (cos (θ))

Apply the common derivative:

\frac{\partial}{\partial θ} (cos (θ)) = - sin (θ)

= r (- sin (θ))

Simplify

= - r sin (θ)

x^{\frac{1}{x}}

\frac{d y}{d t} = 2 (y^{2} - y) t

\int 5 x + 4 d x

y = x^{4} - 3 x^{2} + 10, at x = 1

x \cdot y^{^{'}} = y + 2

What is (\partial)/(\partial θ)(rcos(θ)) ?
The answer to (\partial)/(\partial θ)(rcos(θ)) is -rsin(θ)