What is the derivative of 3x^2+4x-1 ?

The derivative of 3x^2+4x-1 is 6x+4

What is the first derivative of 3x^2+4x-1 ?

The first derivative of 3x^2+4x-1 is 6x+4

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\frac{d}{d x} (3 x^{2} + 4 x - 1)

6 x + 4

Solution steps

\frac{d}{d x} (3 x^{2} + 4 x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (4 x) - \frac{d}{d x} (1)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (1) = 0

= 6 x + 4 - 0

Simplify

= 6 x + 4

\int \frac{2 + 2 x}{- x ^{2} - 2 x + 1} d x

\frac{1}{( s ^{2} + 2 s + 2 ) s}

\frac{d y}{d t} = 6 - \frac{1}{100} y

k = 1 \sum \infty \frac{1}{k}

\frac{d}{d x} ((x^{2} - 4)^{3})

What is the derivative of 3x^2+4x-1 ?
The derivative of 3x^2+4x-1 is 6x+4
What is the first derivative of 3x^2+4x-1 ?
The first derivative of 3x^2+4x-1 is 6x+4