What is the d/(dt)(2sin^3(t)) ?

The d/(dt)(2sin^3(t)) is 6sin^2(t)cos(t)

What is the first d/(dt)(2sin^3(t)) ?

The first d/(dt)(2sin^3(t)) is 6sin^2(t)cos(t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d t} (2 sin^{3} (t))

6 sin^{2} (t) cos (t)

Solution steps

\frac{d}{d t} (2 sin^{3} (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d t} (sin^{3} (t))

Apply the chain rule:

3 (sin (t))^{2} \frac{d}{d t} (sin (t))

= 3 (sin (t))^{2} \frac{d}{d t} (sin (t))

\frac{d}{d t} (sin (t)) = cos (t)

= 2 \cdot 3 (sin (t))^{2} cos (t)

Simplify

= 6 sin^{2} (t) cos (t)

y = (x + 1)^{2}, (- 1, 0)

\int k e^{- 2 x} d x

y = \frac{x - 1}{x + 1}

x \to 0 - lim (arccos (e^{- x^{2}}))

(x + 2)^{2} + (y - 3)^{2} = 37, (- 3, - 3)

What is the d/(dt)(2sin^3(t)) ?
The d/(dt)(2sin^3(t)) is 6sin^2(t)cos(t)
What is the first d/(dt)(2sin^3(t)) ?
The first d/(dt)(2sin^3(t)) is 6sin^2(t)cos(t)