What is the integral from-1 to 1 of 3^x ?

The integral from-1 to 1 of 3^x is 8/(3ln(3))

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integral from-1 to 1 of 3^x

\int_{- 1}^{1} 3^{x} d x

\frac{8}{3 ln ( 3 )}

Decimal Notation

2.42730 \dots

Solution steps

\int_{- 1}^{1} 3^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{3 ^{x}}{ln ( 3 )}]_{- 1}^{1}

Compute the boundaries:

\frac{8}{3 ln ( 3 )}

= \frac{8}{3 ln ( 3 )}

f (x) = 18 x, (9, 54)

\frac{d}{d x} ((2 x + 5)^{3})

y^{^{'}} = x e^{x + y}

\frac{d}{d x} (x^{3} - 3 x^{2} - 9 x + 4)

s^{- \frac{3}{2}}

What is the integral from-1 to 1 of 3^x ?
The integral from-1 to 1 of 3^x is 8/(3ln(3))