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Popular >

xy^'-sqrt(4y^2)=x^2

Solution

x y^{^{'}} - 4 y^{2} = x^{2}

Solution

y = ln (x) x^{2} + c_{1} x^{2}

Solution steps

x y^{'} (x) - 4 y^{2} = x^{2}

Solve linear ODE:

y = ln (x) x^{2} + c_{1} x^{2}

y = ln (x) x^{2} + c_{1} x^{2}

Popular Examples

derivative of (3x-2/(sqrt(2x+1)))

\frac{d}{d x} (\frac{3 x - 2}{2 x + 1})

tangent of f(x)=-1/(x+2),\at x=3 tangent of

f (x) = - \frac{1}{x + 2}, at x = 3

(\partial)/(\partial x)(e^xcos(x))

\frac{\partial}{\partial x} (e^{x} cos (x))

derivative of f(x)=x^2+5 derivative of

f (x) = x^{2} + 5

derivative of cos(2x+pi)

\frac{d}{d x} (cos (2 x + π))

Frequently Asked Questions (FAQ)

What is the solution for xy^'-sqrt(4y^2)=x^2 ?
The solution for xy^'-sqrt(4y^2)=x^2 is y=ln(x)x^2+c_{1}x^2