What is the derivative of-4.9x^2+37 ?

The derivative of-4.9x^2+37 is -9.8x

What is the first derivative of-4.9x^2+37 ?

The first derivative of-4.9x^2+37 is -9.8x

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\frac{d}{d x} (- 4.9 x^{2} + 37)

- 9.8 x

Solution steps

\frac{d}{d x} (- 4.9 x^{2} + 37)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (4.9 x^{2}) + \frac{d}{d x} (37)

\frac{d}{d x} (4.9 x^{2}) = 9.8 x

\frac{d}{d x} (37) = 0

= - 9.8 x + 0

Simplify

= - 9.8 x

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What is the derivative of-4.9x^2+37 ?
The derivative of-4.9x^2+37 is -9.8x
What is the first derivative of-4.9x^2+37 ?
The first derivative of-4.9x^2+37 is -9.8x