What is the integral of x^2sqrt(x^2-25) ?

The integral of x^2sqrt(x^2-25) is

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integral of x^2sqrt(x^2-25)

\int x^{2} x^{2} - 25 d x

625 (\frac{1}{1875} x^{3} x^{2} - 25 - \frac{1}{7500} x^{3} x^{2} - 25 - \frac{1}{200} x x^{2} - 25 - \frac{1}{8} ln (\frac{1}{5} x^{2} - 25 + x)) + C

Solution steps

\int x^{2} x^{2} - 25 d x

Multiply by the conjugate of

x^{2} - 25 : \frac{x ^{4} - 625}{x ^{2} + 25}

= \int x^{2} \frac{x ^{4} - 625}{x ^{2} + 25} d x

Apply Integral Substitution

= \int 625 u^{2} (u + 1) (u - 1) d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 625 \cdot \int u^{2} (u + 1) (u - 1) d u

Multiply by the conjugate of

u + 1 : \frac{u ^{2} - 1}{u - 1}

= 625 \cdot \int u^{2} \frac{u ^{2} - 1}{u - 1} (u - 1) d u

Multiply

\frac{u ^{2} - 1}{u - 1} (u - 1) : u^{2} - 1

= 625 \cdot \int u^{2} u^{2} - 1 d u

Apply Integration By Parts

: \frac{1}{3} u^{3} u^{2} - 1 - \int \frac{u ^{4}}{3 u ^{2} - 1} d u

= 625 (\frac{1}{3} u^{3} u^{2} - 1 - \int \frac{u ^{4}}{3 u ^{2} - 1} d u)

\int \frac{u ^{4}}{3 u ^{2} - 1} d u = \frac{1}{12} u^{3} u^{2} - 1 + \frac{1}{8} (u u^{2} - 1 + ln u^{2} - 1 + u)

= 625 (\frac{1}{3} u^{3} u^{2} - 1 - (\frac{1}{12} u^{3} u^{2} - 1 + \frac{1}{8} (u u^{2} - 1 + ln u^{2} - 1 + u)))

Substitute back

u = \frac{x}{5}

= 625 (\frac{1}{3} (\frac{x}{5})^{3} (\frac{x}{5})^{2} - 1 - (\frac{1}{12} (\frac{x}{5})^{3} (\frac{x}{5})^{2} - 1 + \frac{1}{8} (\frac{x}{5} (\frac{x}{5})^{2} - 1 + ln (\frac{x}{5})^{2} - 1 + \frac{x}{5})))

Simplify

625 (\frac{1}{3} (\frac{x}{5})^{3} (\frac{x}{5})^{2} - 1 - (\frac{1}{12} (\frac{x}{5})^{3} (\frac{x}{5})^{2} - 1 + \frac{1}{8} (\frac{x}{5} (\frac{x}{5})^{2} - 1 + ln (\frac{x}{5})^{2} - 1 + \frac{x}{5}))) : 625 (\frac{1}{1875} x^{3} x^{2} - 25 - \frac{1}{7500} x^{3} x^{2} - 25 - \frac{1}{200} x x^{2} - 25 - \frac{1}{8} ln (\frac{1}{5} x^{2} - 25 + x))

= 625 (\frac{1}{1875} x^{3} x^{2} - 25 - \frac{1}{7500} x^{3} x^{2} - 25 - \frac{1}{200} x x^{2} - 25 - \frac{1}{8} ln (\frac{1}{5} x^{2} - 25 + x))

Add a constant to the solution

= 625 (\frac{1}{1875} x^{3} x^{2} - 25 - \frac{1}{7500} x^{3} x^{2} - 25 - \frac{1}{200} x x^{2} - 25 - \frac{1}{8} ln (\frac{1}{5} x^{2} - 25 + x)) + C

y^{^{'}} + \frac{1}{t} y = 0

n = 1 \sum \infty (\frac{x}{n})^{n}

y = x^{3} - x, (1, 0)

\frac{d}{d x} (\frac{x}{x ^{2} - 15})

\int \frac{9}{( x - 2 ) ( x ^{2} + 4 )} d x