What is the derivative of (((0.06x^2+17x+340))/x) ?

The derivative of (((0.06x^2+17x+340))/x) is (0.06x^2-340)/(x^2)

What is the first derivative of (((0.06x^2+17x+340))/x) ?

The first derivative of (((0.06x^2+17x+340))/x) is (0.06x^2-340)/(x^2)

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\frac{d}{d x} (\frac{( ( 0.06 x ^{2} ) + 17 x + 340 )}{x})

\frac{0.06 x ^{2} - 340}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{( ( 0.06 x ^{2} ) + 17 x + 340 )}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 0.06 x ^{2} + 17 x + 340 ) x - \frac{d x}{d x} ( 0.06 x ^{2} + 17 x + 340 )}{x ^{2}}

\frac{d}{d x} (0.06 x^{2} + 17 x + 340) = 0.12 x + 17

\frac{d x}{d x} = 1

= \frac{( 0.12 x + 17 ) x - 1 \cdot ( 0.06 x ^{2} + 17 x + 340 )}{x ^{2}}

Simplify

\frac{( 0.12 x + 17 ) x - 1 \cdot ( 0.06 x ^{2} + 17 x + 340 )}{x ^{2}} : \frac{0.06 x ^{2} - 340}{x ^{2}}

= \frac{0.06 x ^{2} - 340}{x ^{2}}

\frac{d}{d x} (\frac{sin ( x )}{x})

\int 11 z^{3} e^{z} d z

2 e^{\frac{t}{2}}

\int_{0}^{1} y 1 - y^{2} d y

y = arctan (1) - x^{1} + x

What is the derivative of (((0.06x^2+17x+340))/x) ?
The derivative of (((0.06x^2+17x+340))/x) is (0.06x^2-340)/(x^2)
What is the first derivative of (((0.06x^2+17x+340))/x) ?
The first derivative of (((0.06x^2+17x+340))/x) is (0.06x^2-340)/(x^2)