en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=8(y^2+1)

Solution

y^{^{'}} = 8 (y^{2} + 1)

Solution

y = tan (8 t + c_{1})

Solution steps

y^{'} (t) = 8 (y^{2} + 1)

Solve separable ODE:

y = tan (8 t + c_{1})

y = tan (8 t + c_{1})

Popular Examples

integral of xtan(x^2-1)

\int x tan (x^{2} - 1) d x

integral of xsqrt(x^2+8)

\int x x^{2} + 8 d x

limit as x approaches 0 of ln(x-1)

x \to 0 lim (ln (x - 1))

x(dy}{dx}+2y=\frac{sin(x))/x

x \frac{d y}{d x} + 2 y = \frac{sin ( x )}{x}

integral of cos(x/7)

\int cos (\frac{x}{7}) d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=8(y^2+1) ?
The solution for y^'=8(y^2+1) is y=tan(8t+c_{1})