What is the tangent of f(x)=x+sqrt(x),\at x=25 ?

The tangent of f(x)=x+sqrt(x),\at x=25 is y= 11/10 x+5/2

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tangent of f(x)=x+sqrt(x),\at x=25

tangent of

f (x) = x + x, at x = 25

y = \frac{11}{10} x + \frac{5}{2}

Solution steps

Find the tangent point:

(25, 30)

Find the slope of

f (x) = x + x : \frac{df ( x )}{d x} = 1 + \frac{1}{2 x}

Compute the slope of

f (x) = x + x

x = 25 : m = \frac{11}{10}

Find the line with slope m=

\frac{11}{10}

and passing through

(25, 30) : y = \frac{11}{10} x + \frac{5}{2}

y = \frac{11}{10} x + \frac{5}{2}

y = x^{- 9}

\frac{d}{d x} (10 sin^{3} (x))

\frac{\partial}{\partial x} (y^{3} cos (3 x))

e^{3 x} + 1, y = 0, x = 0, x = 0.6

y^{^{''}} + 14 y^{^{'}} + 49 y = 0, y (0) = 0, y^{^{'}} (0) = 1

What is the tangent of f(x)=x+sqrt(x),\at x=25 ?
The tangent of f(x)=x+sqrt(x),\at x=25 is y= 11/10 x+5/2