What is the tangent of f(x)= 2/x ,(3, 2/3) ?

The tangent of f(x)= 2/x ,(3, 2/3) is y=-2/9 x+4/3

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tangent of f(x)= 2/x ,(3, 2/3)

tangent of

f (x) = \frac{2}{x}, (3, \frac{2}{3})

y = - \frac{2}{9} x + \frac{4}{3}

Solution steps

Find the slope of

f (x) = \frac{2}{x} : \frac{df ( x )}{d x} = - \frac{2}{x ^{2}}

Compute the slope of

f (x) = \frac{2}{x}

(3, \frac{2}{3}) : m = - \frac{2}{9}

Find the line with slope m=

- \frac{2}{9}

and passing through

(3, \frac{2}{3}) : y = - \frac{2}{9} x + \frac{4}{3}

y = - \frac{2}{9} x + \frac{4}{3}

f (x) = \frac{x + 6}{x - 4}

1 + x

y = (4 x - 1)^{2}

\frac{d}{d x} ((3 x + 4) (- 3 + 2 x))

\int (3 x + 8)^{\frac{2}{3}} d x

What is the tangent of f(x)= 2/x ,(3, 2/3) ?
The tangent of f(x)= 2/x ,(3, 2/3) is y=-2/9 x+4/3