en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=4y+1

Solution

y^{^{'}} = 4 y + 1

Solution

y = \frac{e ^{4 t + c_{1}}}{4} - \frac{1}{4}

Solution steps

y^{'} (t) = 4 y + 1

Solve separable ODE:

y = \frac{e ^{4 t + c_{1}}}{4} - \frac{1}{4}

y = \frac{e ^{4 t + c_{1}}}{4} - \frac{1}{4}

Popular Examples

derivative of f(x)=(\sqrt[3]{4x^4+5x^3})derivative of

integral from 2 to 4 of (6-x-y)/8

\int_{2}^{4} \frac{6 - x - y}{8} d y

sum from n=1 to infinity of n/(2^n+5)

n = 1 \sum \infty \frac{n}{2 ^{n} + 5}

(\partial)/(\partial y)(-e^xcos(y))

\frac{\partial}{\partial y} (- e^{x} cos (y))

derivative of (x+2^4-(x+2)^{-2})

\frac{d}{d x} ((x + 2)^{4} - (x + 2)^{- 2})

Frequently Asked Questions (FAQ)

What is the solution for y^'=4y+1 ?
The solution for y^'=4y+1 is y=(e^{4t+c_{1}})/4-1/4