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Popular >

derivative of f(x)=(x-4)/(x+2)

Solution

derivative of

f (x) = \frac{x - 4}{x + 2}

Solution

\frac{6}{( x + 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x - 4}{x + 2})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x - 4 ) ( x + 2 ) - \frac{d}{d x} ( x + 2 ) ( x - 4 )}{( x + 2 ) ^{2}}

\frac{d}{d x} (x - 4) = 1

\frac{d}{d x} (x + 2) = 1

= \frac{1 \cdot ( x + 2 ) - 1 \cdot ( x - 4 )}{( x + 2 ) ^{2}}

Simplify

\frac{1 \cdot ( x + 2 ) - 1 \cdot ( x - 4 )}{( x + 2 ) ^{2}} : \frac{6}{( x + 2 ) ^{2}}

= \frac{6}{( x + 2 ) ^{2}}

Popular Examples

tangent of x/(sqrt(36+x^2))tangent of

\frac{x}{36 + x ^{2}}

x^2ydy-xy^2dx-x^3y^2dx=0

x^{2} y d y - x y^{2} d x - x^{3} y^{2} d x = 0

integral of (2x)/(1+2x^2)

\int \frac{2 x}{1 + 2 x ^{2}} d x

tangent of f(x)=(5x-1)^4,\at x=2 tangent of

f (x) = (5 x - 1)^{4}, at x = 2

(\partial)/(\partial x)(x^2*e^x)

\frac{\partial}{\partial x} (x^{2} \cdot e^{x})

Frequently Asked Questions (FAQ)

What is the derivative of f(x)=(x-4)/(x+2) ?
The derivative of f(x)=(x-4)/(x+2) is 6/((x+2)^2)
What is the first derivative of f(x)=(x-4)/(x+2) ?
The first derivative of f(x)=(x-4)/(x+2) is 6/((x+2)^2)