What is the derivative of f(1)=-x^2+6x-3 ?

The derivative of f(1)=-x^2+6x-3 is -2x+6

What is the first derivative of f(1)=-x^2+6x-3 ?

The first derivative of f(1)=-x^2+6x-3 is -2x+6

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derivative of

f (1) = - x^{2} + 6 x - 3

- 2 x + 6

Solution steps

\frac{d}{d x} (- x^{2} + 6 x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (6 x) - \frac{d}{d x} (3)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (3) = 0

= - 2 x + 6 - 0

Simplify

= - 2 x + 6

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\frac{d}{d x} (x cos (y))

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What is the derivative of f(1)=-x^2+6x-3 ?
The derivative of f(1)=-x^2+6x-3 is -2x+6
What is the first derivative of f(1)=-x^2+6x-3 ?
The first derivative of f(1)=-x^2+6x-3 is -2x+6